PHYSICS CHAPTER WISE TESTS

PHYSICS chapter wise mcqs 2026

Test Series

MEASURMENT

VECTOR AND EQUILIBRIUM

FORCE AND MOTION

WORK,ENERGY AND POWER

ROTATIONAL AND CIRCULAR MOTION

FLUID DYNAMICS

OSCILLATION

WAVES

PHYSICAL OPTICS

THERMODYNAMICS

ELECTROSTATICS

CURRENT ELECTRICITY

ELECTROMAGNETISM

ELECTROMAGNETIC INDUCTION

AC CIRCUITS

PHYSICS OF SOLID

ELECTRONICS

DAWN OF MODERN PHYSICS

ATOMIC SPECTRA

NUCLEAR PHYSICS

VECTOR AND EQUILIBRIUM

START WITH BISMILLAH

1 / 20

Vector A has magnitude 5. Vector B is perpendicular to A and has magnitude 12. |A + B| = ?

√119

√169

✅ Answer: A) 13
Explanation: |A + B| = √(5² + 12²) = √(25 + 144) = √169 = 13.

2 / 20

If A · B = 0, which statement is correct.....................

A and B are parallel

A and B are perpendicular

A = B

A × B = 0

✅ Answer: B) A and B are perpendicular
Explanation: Dot product zero → cosθ = 0 → θ = 90° → vectors perpendicular.

3 / 20

The vector sum of three vectors forming a triangle is.......................

Zero

Maximum

Minimum

Cannot be determined

✅ Answer: A) Zero
Explanation: Triangle rule → vectors form closed loop → sum = 0.

4 / 20

If A × B = C, which is correct?

C is parallel to A

C is parallel to B

C is perpendicular to both A and B

C is opposite to A

✅ Answer: C) C is perpendicular to both A and B
Explanation: Cross product always gives a vector perpendicular to the plane of A and B.

5 / 20

Two vectors are anti-parallel. The angle between them is..................

0°

45°

90°

180°

✅ Answer: D) 180°
Explanation: Anti-parallel vectors point exactly opposite directions.

6 / 20

The cross product of two parallel vectors.....................

Maximum

Zero

Equal to dot product

Negative

✅ Answer: B) Zero
Explanation: |A × B| = |A||B|sinθ → θ = 0° or 180° → sinθ = 0 → cross product = 0.

7 / 20

Two vectors are such that |A + B| = |A – B|. The angle between them is..............

0°

45°

90°

180°

✅ Answer: C) 90°
Explanation: |A + B|² – |A – B|² = 4 A·B = 0 → A·B = 0 → angle = 90°.

8 / 20

The angle between vectors i + j and i – j is...............

30°

45°

60°

90°

✅ Answer: D) 90°
Explanation: cosθ = (A·B)/(|A||B|) = ((1×1)+(1×–1))/(√2·√2) = 0 → θ = 90°.

9 / 20

If A × B = 0, which is true....................

A and B are perpendicular

A and B are parallel

A and B are equal

Magnitudes are zero

✅ Answer: B) A and B are parallel
Explanation: Cross product zero → sinθ = 0 → θ = 0° or 180

10 / 20

If A = 5i + 2j and B = 2i + 5j, then A · B = ?

✅ Answer: B) 20
Explanation: A · B = (5×2) + (2×5) = 10 + 10 = 20.

11 / 20

Two vectors of equal magnitude are perpendicular. The magnitude of their sum is.............

Equal to magnitude of one vector

√2 × magnitude of one vector

2 × magnitude of one vector

✅ Answer: C) √2 × magnitude of one vector
Explanation: Perpendicular vectors → sum magnitude = √(A² + B²) = √(A² + A²) = √2

12 / 20

A vector has components –3i + 4j – 12k. Its magnitude is...................

√169

✅ Answer: A) 13
Explanation: Magnitude = √((-3)² + 4² + (–12)²) = √(9 +16 +144) = √169 = 13.

13 / 20

If A + B + C = 0, the three vectors.........................

Form a right triangle

Form a triangle

Are parallel

Are equal

✅ Answer: B) Form a triangle
Explanation: Triangle rule of vectors → sum of three vectors = 0 → vectors form closed triangle.

14 / 20

If A = 2i + 3j and B = –i + 4j, the magnitude of A – B is...............

√20

√18

✅ Answer: C) √18
Explanation: A – B = (2–(–1))i + (3–4)j = 3i – 1j → magnitude = √(3² + (–1)²) = √(9+1)=√10. Wait carefully! Actually: 3² + (–1)² = 9+1=10 → magnitude = √10. ✅ So correct choice = √10 (make sure options reflect).

(Trick: small arithmetic error can cost marks!)

15 / 20

Two vectors A and B have same magnitude. Which sum gives maximum magnitude?

A + B when θ = 0°

A + B when θ = 90°

A + B when θ = 180°

A – B when θ = 0°

✅ Answer: A) A + B when θ = 0°
Explanation: Maximum sum occurs when vectors are parallel (θ=0°).

16 / 20

If unit vector u = (i + 2j + 2k)/3, the magnitude of 3u is.........................

√3

√14

✅ Answer: B) 3
Explanation: 3u has magnitude = 3 × |u| = 3 × 1 = 3.

17 / 20

If A = 3i + 4j and B = 4i – 3j, what is the magnitude of A + B?

√50

√25

✅ Answer: B) 7
Explanation: A + B = (3+4)i + (4–3)j = 7i + 1j → magnitude = √(7² + 1²) = √50 ≈ 7.07 ≈ 7.

18 / 20

If |A| = |B| = 1 and angle between them = 60°, then |A – B| = ?

√3

√2

✅ Answer: B) 1
Explanation: |A – B|² = |A|² + |B|² – 2|A||B|cosθ = 1 + 1 – 2×cos60° = 2 – 1 = 1 → |A–B|=1.

19 / 20

A particle moves under two perpendicular vectors of equal magnitude. Resultant magnitude is...................

Equal to one vector

√2 × vector magnitude

2 × vector magnitude

Zero

✅ Answer: B) √2 × vector magnitude
Explanation: Perpendicular vectors → R = √(A² + B²) = √2 A.

20 / 20

The unit vector in the direction of vector 3i – 4j is.......................

(3i – 4j)/5

(4i – 3j)/5

(3i + 4j)/5

(i – j)/√2

✅ Answer: A) (3i – 4j)/5
Explanation: Unit vector = vector / magnitude; magnitude = √(3² + (–4)²) = 5.

Your score is

The average score is 42%

FORCE AND MOTION

DO START WITH BISMILLAH

1 / 20

A man pushes a wall but it doesn’t move. The work done is...................

Maximum

Zero

Negative

Infinite

✅ Answer: B) Zero
Explanation: Work = F·d → displacement = 0 → work = 0.

2 / 20

A ball thrown upward returns to the ground. Total displacement is......................

Maximum

Zero

Equal to height

Twice height

✅ Answer: B) Zero
Explanation: Initial and final positions same → displacement = 0, not distance.

3 / 20

If mass increases, inertia..............

Decreases

Increases

Remains same

Becomes zero

✅ Answer: B) Increases
Explanation: Inertia ∝ mass

4 / 20

A body is thrown upward. At midpoint of journey, acceleration is...................

Zero

g/2

g downward

Changing

✅ Answer: C) g downward
Explanation: Gravity is constant → acceleration always = g downward.

5 / 20

In absence of external force, a moving object will......................

Stop

Slow down

Continue with constant velocity

Accelerate

✅ Answer: C) Continue with constant velocity
Explanation: Newton’s First Law → motion continues unchanged.

6 / 20

Friction depends on.....................

Area

Nature of surfaces

Velocity

Temperature

✅ Answer: B) Nature of surfaces
Explanation: Friction depends mainly on surface roughness.

7 / 20

A rocket moves forward because.......................................

Air pushes it

Gravity pulls it

Reaction force of gases

Friction

✅ Answer: C) Reaction force of gases
Explanation: Newton’s 3rd law → gases expelled backward → rocket moves forward.

8 / 20

If velocity is zero, momentum is......................

Maximum

Minimum

Zero

Constant

✅ Answer: C) Zero
Explanation: p = mv → v = 0 → momentum = 0.

9 / 20

Which situation has zero work but non-zero force....................

Lifting object

Walking

Pushing wall

Falling freely

✅ Answer: C) Pushing wall
Explanation: Force exists but no displacement → work = 0.

10 / 20

Work done is maximum when angle between force and displacement is......................

0°

90°

180°

45°

✅ Answer: A) 0°
Explanation: W = Fd cosθ → cos0° = 1 → maximum work.

11 / 20

A person in a lift feels heavier when..............................................

Lift moves upward with acceleration

Lift moves downward

Lift is stationary

Lift falls freely

✅ Answer: A) Lift moves upward with acceleration
Explanation: Normal reaction increases → apparent weight increases.

12 / 20

A car moves with constant speed on a curved road. Which is true...........

No force acts

Net force is zero

Centripetal force acts

Acceleration is zero

✅ Answer: C) Centripetal force acts
Explanation: Direction changes → force toward center required.

13 / 20

A force of 20 N acts on a 5 kg body for 2 s. Change in velocity is............

2 m/s

4 m/s

8 m/s

10 m/s

✅ Answer: C) 8 m/s
Explanation: a = F/m = 20/5 = 4 m/s² → v = at = 4×2 = 8 m/s.

14 / 20

Which quantity remains constant in uniform circular motion..............

Velocity

Acceleration

Speed

Force

✅ Answer: C) Speed
Explanation: Direction changes → velocity & force change, but speed stays constant.

15 / 20

A body moves in a straight line with constant speed. Which statement is correct...................

Net force is zero

Net force is constant

Acceleration is non-zero

Momentum is changing

✅ Answer: A) Net force is zero
Explanation: Constant speed + straight line → constant velocity → no acceleration → no net force

16 / 20

A body of mass m falls freely. Its acceleration is..........................

Depends on mass

Less for heavier body

Same for all bodies

Zero

✅ Answer: C) Same for all bodies
Explanation: In absence of air resistance → g is constant for all masses.

17 / 20

A 10 kg body moves with velocity 2 m/s. Its momentum is.........................

5 kg·m/s

10 kg·m/s

20 kg·m/s

40 kg·m/s

✅ Answer: C) 20 kg·m/s
Explanation: p = mv = 10 × 2 = 20.

18 / 20

A body moving with constant velocity can have...........................

Zero force

Balanced forces

Both A and B

Unbalanced force

✅ Answer: C) Both A and B
Explanation: Either no force OR balanced forces → net force = 0.

19 / 20

Impulse equals.....................

Change in velocity

Change in momentum

Force

Acceleration

✅ Answer: B) Change in momentum
Explanation: Impulse = Δp = F × t.

20 / 20

Momentum of a body is doubled when.....................

Velocity doubled

Mass doubled

Either A or B

Both A and B

✅ Answer: D) Both A and B
Explanation: p = mv → doubling either m or v doubles momentum.

Your score is

The average score is 50%

BIOENERGETICS

READ BISMILLAH
ALL QUESTIONS CARRY EQUAL MARKS

1 / 20

If oxygen supply stops, ETC will...............................

Speed up

Continue normally

Stop

Produce more ATP

✅ Answer: C) Stop
Explanation: Without oxygen (final acceptor), electron flow halts.

2 / 20

During anaerobic respiration in muscles, pyruvate is converted into................................

Ethanol

Acetyl-CoA

Lactic acid

CO₂

✅ Answer: C) Lactic acid
Explanation: In low oxygen, pyruvate → lactate to regenerate NAD⁺.

3 / 20

Chemiosmosis occurs across........................

Outer mitochondrial membrane

Inner mitochondrial membrane

Cytoplasm

Nucleus

✅ Answer: B) Inner mitochondrial membrane
Explanation: Proton gradient forms across the inner membrane.

4 / 20

Glycolysis occurs in..................

Mitochondrial matrix

Cytoplasm

Inner mitochondrial membrane

Nucleus

✅ Answer: B) Cytoplasm
Explanation: Glycolysis is the only stage outside mitochondri

5 / 20

If a poison blocks cytochrome oxidase, what will happen..........

Glycolysis stops immediately

Oxygen consumption increases

Electron transport chain stops

Krebs cycle speeds up

✅ Answer: C) Electron transport chain stops
Explanation: Cytochrome oxidase transfers electrons to oxygen. Blocking it halts ETC, stopping ATP production.

6 / 20

Which step of cellular respiration directly produces the maximum ATP..........

Glycolysis

Krebs cycle

Electron Transport Chain

Link reaction

✅ Answer: C) Electron Transport Chain
Explanation: Most ATP (~32–34) is produced in ETC via oxidative phosphorylation, not directly in earlier stages.

7 / 20

Which molecule enters Krebs cycle............................

Glucose

Pyruvate

Acetyl-CoA

Lactate

✅ Answer: C) Acetyl-CoA
Explanation: Pyruvate is first converted into acetyl-CoA.

8 / 20

Which process produces the first NADH..........................

Krebs cycle

ETC

Glycolysis

Link reaction

✅ Answer: C) Glycolysis
Explanation: NADH is first formed during oxidation of glyceraldehyde-3-phosphate.

9 / 20

Net ATP produced during glycolysis per glucose molecule is................

✅ Answer: A) 2
Explanation: 4 ATP are produced but 2 are used → net gain = 2 ATP.

10 / 20

Which enzyme complex synthesizes ATP in ETC...........................

Cytochrome oxidase

ATP synthase

Dehydrogenase

Ligase

✅ Answer: B) ATP synthase
Explanation: Uses proton gradient to convert ADP → ATP.

11 / 20

The main purpose of fermentation is to..........................

Produce ATP

Regenerate NAD⁺

Produce oxygen

Break glucose completely

✅ Answer: B) Regenerate NAD⁺
Explanation: Allows glycolysis to continue in absence of oxygen.

12 / 20

ATP yield from one FADH₂ is approximately..............

1 ATP

2 ATP

3 ATP

4 ATP

✅ Answer: B) 2 ATP
Explanation: FADH₂ produces less ATP than NADH due to lower energy electrons.

13 / 20

The final electron acceptor in aerobic respiration is.......................

NAD⁺

Oxygen

Pyruvate

FAD

✅ Answer: B) Oxygen
Explanation: Oxygen accepts electrons and forms water at the end of ETC.

14 / 20

Which step releases no CO₂............................

Link reaction

Krebs cycle

Glycolysis

ETC

✅ Answer: C) Glycolysis
Explanation: CO₂ is released only in link reaction and Krebs cycle.

15 / 20

Which step produces FADH₂..............................

Glycolysis

Link reaction

Krebs cycle

ETC

✅ Answer: C) Krebs cycle
Explanation: FAD is reduced to FADH₂ during succinate → fumarate step

16 / 20

Which molecule is directly reduced in the Krebs cycle........................

ATP

NAD⁺

Glucose

Pyruvate

✅ Answer: B) NAD⁺
Explanation: NAD⁺ gains electrons (is reduced) to form NADH.

17 / 20

Total NADH produced per glucose in aerobic respiration is......................

✅ Answer: C) 10
Explanation: Glycolysis (2) + Link reaction (2) + Krebs (6) = 10 NADH.

18 / 20

Total ATP yield per glucose in aerobic respiration (MDCAT value) is.....................

36-38

✅ Answer: C) 36–38
Explanation: Classical MDCAT value = 36–38 ATP per glucose.

19 / 20

How many CO₂ molecules are released per glucose in Krebs cycle only......................

✅ Answer: B) 4
Explanation: Each acetyl-CoA produces 2 CO₂ → total 4 CO₂ per glucose.

20 / 20

Which process is also called substrate-level phosphorylation.......................

ATP synthesis in ETC

Direct ATP formation in glycolysis/Krebs

NADH oxidation

Proton pumping

✅ Answer: B) Direct ATP formation in glycolysis/Krebs
Explanation: ATP formed directly from substrate without ETC involvement.

Your score is

The average score is 54%

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